IGCSE Physics 0625 · Topic 1.5

IGCSE Physics: Forces Practice Questions

A resultant force changes the motion of an object. If the resultant force is zero the object stays at rest or continues at constant velocity, and if it is not zero the object accelerates in the direction of that force, following F = ma.

Cambridge IGCSE Physics (0625) · Topic 1.5: Forces

Sub-topic 1.5 of Cambridge IGCSE Physics 0625 carries more calculation marks than almost any other part of the course, and it feeds directly into momentum, energy and pressure. Nearly every mark is earned by writing the equation, substituting correctly with units, and giving the answer to a sensible number of significant figures. The questions below are structured the way Paper 3 and Paper 4 present them.

What you need to know for Forces

IGCSE Physics Forces questions and answers

4 exam-style questions written to the 0625 syllabus. Try each one on paper first, then open the worked answer to check your method against the marks.

Question 1[3 marks]

A car of mass 1200 kg accelerates at 2.5 m/s2 along a level road. The total resistive force acting on it is 800 N. Calculate the driving force produced by the engine.

Show the worked answer
Answer: 3800 N
  1. Find the resultant force using F = ma.
  2. F = 1200 x 2.5 = 3000 N.
  3. The resultant force is the driving force minus the resistive force, so driving force = resultant + resistive.
  4. Driving force = 3000 + 800 = 3800 N.
How the marks are awarded. 1 mark for using F = ma. 1 mark for a resultant force of 3000 N. 1 mark for adding the 800 N resistive force to give 3800 N with the unit.
Where students lose the mark. Stopping at 3000 N. That is the resultant force, not the driving force. The engine must also overcome the 800 N of resistance.
Question 2[3 marks]

A uniform beam is balanced on a pivot at its centre. A weight of 4.0 N is placed 0.60 m from the pivot on the left. A weight of 3.0 N is placed on the right. Calculate the distance of the 3.0 N weight from the pivot for the beam to balance.

Show the worked answer
Answer: 0.80 m
  1. Apply the principle of moments: clockwise moments equal anticlockwise moments.
  2. Anticlockwise moment = 4.0 x 0.60 = 2.4 N m.
  3. Clockwise moment = 3.0 x d.
  4. So 3.0d = 2.4, giving d = 2.4 / 3.0 = 0.80 m.
How the marks are awarded. 1 mark for using moment = force x distance. 1 mark for equating clockwise and anticlockwise moments, or for 2.4 N m. 1 mark for 0.80 m with the unit.
Where students lose the mark. Adding the two weights or the two distances. Moments are found by multiplying force by distance, then balancing the two totals.
Question 3[4 marks]

A spring extends by 4.0 cm when a load of 2.0 N is hung from it. Calculate the spring constant, then find the extension produced by a load of 5.0 N. Assume the spring stays within its limit of proportionality.

Show the worked answer
Answer: k = 50 N/m, and the extension is 0.10 m or 10 cm.
  1. Convert the extension to metres: 4.0 cm = 0.040 m.
  2. Rearrange F = kx to give k = F / x.
  3. k = 2.0 / 0.040 = 50 N/m.
  4. For 5.0 N: x = F / k = 5.0 / 50 = 0.10 m, which is 10 cm.
How the marks are awarded. 1 mark for converting cm to m. 1 mark for k = 50 N/m. 1 mark for rearranging to x = F / k. 1 mark for 0.10 m or 10 cm.
Where students lose the mark. Leaving the extension in centimetres and reporting k as 0.5 N/cm without saying so. Convert to metres and quote N/m unless the question specifies otherwise.
Question 4[2 marks]

Explain, using Newton's first law, why a passenger not wearing a seat belt continues to move forward when a car brakes suddenly.

Show the worked answer
Answer: No backward force acts on the passenger, so they continue at constant velocity.
  1. The braking force acts on the car, not directly on the passenger.
  2. Newton's first law states that an object continues moving at constant velocity unless a resultant force acts on it.
  3. With no seat belt there is no significant backward force on the passenger, so they keep moving forward at the original speed until they hit something.
How the marks are awarded. 1 mark for stating that no resultant backward force acts on the passenger. 1 mark for the passenger continuing to move at constant velocity, or an equivalent statement of inertia.
Where students lose the mark. Writing that a force pushes the passenger forward. No forward force exists. The passenger simply keeps moving because nothing stops them.

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Forces FAQs

What is the difference between mass and weight?

Mass is the amount of matter in an object, measured in kilograms, and it does not change with location. Weight is the force of gravity acting on that mass, measured in newtons, calculated as W = mg. On the Moon your mass is unchanged but your weight is roughly one sixth of its value on Earth.

How do I calculate a resultant force?

Add forces that act in the same direction and subtract forces that act in opposite directions. The resultant is the single force that would have the same effect. If the resultant is zero the object is in equilibrium, and if it is not zero the object accelerates in the direction of the resultant.

What is the limit of proportionality in Hooke's law?

The limit of proportionality is the point beyond which extension is no longer directly proportional to the load. Up to that point a load extension graph is a straight line through the origin. Beyond it the line curves, and the equation F = kx no longer applies.

What are the units of a moment?

Moments are measured in newton metres, written N m. Multiply the force in newtons by the perpendicular distance from the pivot in metres. If the distance is given in centimetres, convert to metres first unless the question asks for N cm.

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Written to the published Cambridge IGCSE Physics (0625) syllabus. Check your school entry code and syllabus year, because Core and Extended candidates are assessed on different content. Last reviewed 2026-08-12.