IGCSE Physics 0625 · Topic 1.2

IGCSE Physics: Motion Practice Questions

Speed is distance travelled per unit time and acceleration is the change in velocity per unit time. On a distance-time graph the gradient gives speed, and on a speed-time graph the gradient gives acceleration while the area under the line gives distance travelled.

Cambridge IGCSE Physics (0625) · Topic 1.2: Motion

Sub-topic 1.2 of Cambridge IGCSE Physics 0625 is dominated by graph work, and the single most valuable fact in the topic is that the area under a speed-time graph is the distance travelled. The questions below cover the calculations, both graph types and terminal velocity.

What you need to know for Motion

IGCSE Physics Motion questions and answers

4 exam-style questions written to the 0625 syllabus. Try each one on paper first, then open the worked answer to check your method against the marks.

Question 1[3 marks]

A car increases its velocity from 8.0 m/s to 26 m/s in 6.0 s. Calculate its acceleration.

Show the worked answer
Answer: 3.0 m/s2
  1. Use acceleration = change in velocity divided by time taken.
  2. Change in velocity = 26 minus 8.0 = 18 m/s.
  3. Acceleration = 18 divided by 6.0.
  4. Acceleration = 3.0 m/s2.
How the marks are awarded. 1 mark for using acceleration = change in velocity divided by time. 1 mark for a change in velocity of 18 m/s. 1 mark for 3.0 m/s2 with the unit.
Where students lose the mark. Dividing the final velocity by the time instead of the change in velocity. Acceleration always uses the change, not the final value.
Question 2[4 marks]

A speed-time graph shows a cyclist accelerating uniformly from rest to 12 m/s over 8.0 s, then travelling at 12 m/s for a further 20 s. Calculate the total distance travelled.

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Answer: 288 m
  1. The distance travelled is the area under the speed-time graph.
  2. The first section is a triangle: area = half x base x height = 0.5 x 8.0 x 12 = 48 m.
  3. The second section is a rectangle: area = 20 x 12 = 240 m.
  4. Total distance = 48 + 240 = 288 m.
How the marks are awarded. 1 mark for stating that distance is the area under the graph. 1 mark for 48 m for the triangle. 1 mark for 240 m for the rectangle. 1 mark for a total of 288 m with the unit.
Where students lose the mark. Multiplying the maximum speed by the total time, which gives 336 m. That treats the accelerating section as though it were at full speed throughout.
Question 3[5 marks]

A skydiver jumps from a stationary balloon and eventually falls at a constant speed before opening the parachute. Explain, in terms of forces, why she accelerates at first and then reaches a constant speed.

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Answer: Weight initially exceeds air resistance, but air resistance grows with speed until the two balance and the resultant force is zero.
  1. At the moment she jumps, her speed is zero, so air resistance is zero and the only significant force is her weight acting downwards.
  2. There is a large resultant downward force, so she accelerates.
  3. As her speed increases, air resistance increases because she collides with more air particles per second.
  4. The resultant downward force therefore decreases, so her acceleration decreases even though she continues to speed up.
  5. Eventually air resistance equals her weight. The resultant force is zero, so by Newton's first law there is no further acceleration and she falls at a constant speed, her terminal velocity.
How the marks are awarded. 1 mark for weight being the only force initially, with air resistance zero. 1 mark for a large resultant force causing acceleration. 1 mark for air resistance increasing with speed. 1 mark for the resultant force and acceleration decreasing. 1 mark for air resistance equalling weight giving zero resultant force and constant speed.
Where students lose the mark. Saying the forces are balanced so she stops. Balanced forces mean no acceleration, not no motion. She continues at a constant speed.
Question 4[4 marks]

A distance-time graph for a runner shows a straight sloping line from the origin, then a horizontal line, then a steeper straight sloping line. Describe the motion in each of the three sections.

Show the worked answer
Answer: Constant speed, then stationary, then a faster constant speed.
  1. Section 1: a straight sloping line means distance increases at a steady rate, so the runner moves at a constant speed. The speed is the gradient of that line.
  2. Section 2: a horizontal line means the distance is not changing, so the runner is stationary.
  3. Section 3: a straight sloping line again means constant speed.
  4. The third line is steeper than the first, so its gradient is larger and the runner is moving at a greater constant speed than in section 1.
How the marks are awarded. 1 mark for constant speed in section 1. 1 mark for stationary in section 2. 1 mark for constant speed in section 3. 1 mark for the third section being faster because the gradient is steeper.
Where students lose the mark. Reading the horizontal section as the runner moving backwards. A horizontal line on a distance-time graph means no movement at all.

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Motion FAQs

What does the area under a speed-time graph represent?

The area under a speed-time graph gives the distance travelled. Split the area into triangles and rectangles, calculate each and add them. The gradient of the same graph gives the acceleration, so a single speed-time graph provides both quantities.

What is terminal velocity?

Terminal velocity is the constant speed reached by a falling object when air resistance has increased until it equals the object's weight. The resultant force is then zero, so there is no further acceleration and the object continues to fall at a steady speed.

What is the difference between speed and velocity?

Speed is the distance travelled per unit time and is a scalar, so it has magnitude only. Velocity is speed in a stated direction and is a vector. An object moving in a circle at a steady rate has constant speed but changing velocity, because its direction keeps changing.

How do I calculate acceleration?

Divide the change in velocity by the time taken. Subtract the initial velocity from the final velocity first, then divide by the time. The unit is metres per second squared. A negative answer means the object is decelerating.

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Written to the published Cambridge IGCSE Physics (0625) syllabus. Check your school entry code and syllabus year, because Core and Extended candidates are assessed on different content. Last reviewed 2026-08-12.