IGCSE Physics 0625 · Topic 1.6

IGCSE Physics: Momentum Practice Questions

Momentum is mass multiplied by velocity, measured in kg m/s. In any collision or explosion with no external force, the total momentum before the event equals the total momentum after it.

Cambridge IGCSE Physics (0625) · Topic 1.6: Momentum

Sub-topic 1.6 of Cambridge IGCSE Physics 0625 appears on the Extended papers and is almost entirely calculation. Because momentum is a vector, the direction convention you choose at the start decides whether the whole answer works. The questions below make you set that convention every time.

What you need to know for Momentum

IGCSE Physics Momentum questions and answers

4 exam-style questions written to the 0625 syllabus. Try each one on paper first, then open the worked answer to check your method against the marks.

Question 1[4 marks]

A trolley of mass 2.0 kg moving at 3.0 m/s collides with a stationary trolley of mass 4.0 kg. They stick together. Calculate their common velocity after the collision.

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Answer: 1.0 m/s in the original direction of the first trolley.
  1. Take the direction of the moving trolley as positive.
  2. Total momentum before = (2.0 x 3.0) + (4.0 x 0) = 6.0 kg m/s.
  3. After the collision the two trolleys move together, so the combined mass is 2.0 + 4.0 = 6.0 kg.
  4. Momentum is conserved, so 6.0 = 6.0 x v, giving v = 1.0 m/s in the original direction.
How the marks are awarded. 1 mark for stating that momentum is conserved. 1 mark for a total momentum before of 6.0 kg m/s. 1 mark for using a combined mass of 6.0 kg. 1 mark for 1.0 m/s with the unit and direction.
Where students lose the mark. Forgetting to add the masses after the collision. When objects stick together they move as a single object of combined mass.
Question 2[4 marks]

A ball of mass 0.15 kg travelling at 12 m/s hits a wall and rebounds at 8.0 m/s in the opposite direction. Calculate the change in momentum of the ball.

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Answer: 3.0 kg m/s, directed away from the wall.
  1. Take the direction towards the wall as positive, so the rebound velocity is negative.
  2. Momentum before = 0.15 x 12 = 1.8 kg m/s.
  3. Momentum after = 0.15 x (minus 8.0) = minus 1.2 kg m/s.
  4. Change in momentum = final minus initial = minus 1.2 minus 1.8 = minus 3.0 kg m/s. The magnitude is 3.0 kg m/s, directed away from the wall.
How the marks are awarded. 1 mark for taking the rebound velocity as negative. 1 mark for a momentum before of 1.8 kg m/s. 1 mark for a momentum after of minus 1.2 kg m/s. 1 mark for a change of 3.0 kg m/s with the unit.
Where students lose the mark. Subtracting the speeds to get 4 m/s and calculating 0.6 kg m/s. The ball reverses direction, so the velocities have opposite signs and the change is larger, not smaller.
Question 3[4 marks]

Explain how a car's crumple zone reduces the force on the driver during a crash.

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Answer: It increases the collision time, and force equals change in momentum divided by time.
  1. During a crash the driver's momentum falls to zero. That change in momentum is fixed by the mass and the speed before impact.
  2. Force equals change in momentum divided by the time taken for that change.
  3. A crumple zone deforms progressively rather than stopping instantly, so the car and the driver take longer to come to rest.
  4. Since the change in momentum is the same but the time is longer, the force acting on the driver is smaller, so injuries are less severe. Airbags and seat belts work on the same principle.
How the marks are awarded. 1 mark for the change in momentum being fixed. 1 mark for force = change in momentum divided by time. 1 mark for the crumple zone increasing the time of the collision. 1 mark for a longer time giving a smaller force.
Where students lose the mark. Saying the crumple zone absorbs the force. It extends the time over which the momentum changes, which is what reduces the force.
Question 4[4 marks]

A stationary firework of mass 0.80 kg explodes into two pieces. One piece of mass 0.30 kg moves east at 20 m/s. Calculate the velocity of the other piece.

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Answer: 12 m/s west.
  1. Take east as positive. Total momentum before the explosion is zero, because the firework was stationary.
  2. Momentum is conserved, so total momentum after must also be zero.
  3. Momentum of the first piece = 0.30 x 20 = 6.0 kg m/s east.
  4. The second piece has mass 0.80 minus 0.30 = 0.50 kg, and must carry minus 6.0 kg m/s. So v = minus 6.0 divided by 0.50 = minus 12 m/s, meaning 12 m/s west.
How the marks are awarded. 1 mark for total momentum before being zero. 1 mark for a mass of 0.50 kg for the second piece. 1 mark for the second momentum being 6.0 kg m/s in the opposite direction. 1 mark for 12 m/s west.
Where students lose the mark. Using 0.80 kg for the second piece. Subtract the mass of the first piece from the total to find the mass of the second.

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Momentum FAQs

What is the principle of conservation of momentum?

In a closed system where no external resultant force acts, the total momentum before an event equals the total momentum after it. This applies to collisions, where objects come together, and to explosions, where an object separates into pieces.

How do I handle direction in momentum calculations?

Choose one direction as positive before starting, and treat any velocity in the opposite direction as negative. The signs then handle the vector nature of momentum automatically. State your convention in the working, because examiners award marks for a consistent method.

Why do airbags reduce injury?

The change in momentum a passenger experiences is fixed by their mass and the speed of the crash. Force equals change in momentum divided by time, so extending the time over which the passenger slows reduces the force acting on them. An airbag increases that time.

What is impulse?

Impulse is force multiplied by the time for which it acts, and it equals the change in momentum produced. Its unit, the newton second, is equivalent to kg m/s. This relationship is why a small force acting for a long time can produce the same change as a large force acting briefly.

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Written to the published Cambridge IGCSE Physics (0625) syllabus. Check your school entry code and syllabus year, because Core and Extended candidates are assessed on different content. Last reviewed 2026-08-12.