IGCSE Mathematics 0580 · Topic 5.4

IGCSE Mathematics: Volume and Surface Area Practice Questions

The volume of any prism is the cross sectional area multiplied by the length. Cones and pyramids take one third of the equivalent prism, and a sphere has volume four thirds pi r cubed.

Cambridge IGCSE Mathematics (0580) · Topic 5.4: Volume and Surface Area

Topic 5.4 of Cambridge IGCSE Mathematics 0580 supplies formulas that are printed on the front of the paper, so the marks come from choosing the right one and reading whether the surface area required is curved or total. The questions below test that distinction.

What you need to know for Volume and Surface Area

IGCSE Mathematics Volume and Surface Area questions and answers

4 exam-style questions written to the 0580 syllabus. Try each one on paper first, then open the worked answer to check your method against the marks.

Question 1[3 marks]

A cylinder has a radius of 5 cm and a height of 12 cm. Calculate its volume, correct to 3 significant figures.

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Answer: 943 cm3
  1. A cylinder is a prism, so volume = cross sectional area x height = pi r2 h.
  2. The cross sectional area is pi x 52 = pi x 25 = 78.54 cm2.
  3. Volume = 78.54 x 12 = 942.48 cm3.
  4. To 3 significant figures the volume is 943 cm3.
How the marks are awarded. 1 mark for using pi r2 h. 1 mark for a cross sectional area of 78.5. 1 mark for 943 cm3 with the unit.
Where students lose the mark. Using 2 pi r instead of pi r squared for the cross section. That formula gives the circumference, not the area.
Question 2[4 marks]

For the same cylinder, radius 5 cm and height 12 cm, calculate the curved surface area and the total surface area, correct to 3 significant figures.

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Answer: Curved surface area 377 cm2 and total surface area 534 cm2.
  1. Curved surface area = 2 pi r h = 2 x pi x 5 x 12 = 376.99 cm2, which is 377 cm2.
  2. The two circular ends each have area pi r2 = pi x 25 = 78.54 cm2.
  3. Two ends contribute 2 x 78.54 = 157.08 cm2.
  4. Total surface area = 376.99 + 157.08 = 534.07, which is 534 cm2 to 3 significant figures.
How the marks are awarded. 1 mark for using 2 pi r h. 1 mark for 377 cm2. 1 mark for adding two circular ends. 1 mark for 534 cm2.
Where students lose the mark. Adding only one circular end. A closed cylinder has two, and an open one has none, so read the question carefully.
Question 3[5 marks]

A cone has a radius of 6 cm and a perpendicular height of 8 cm. Calculate its volume and its curved surface area, correct to 3 significant figures.

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Answer: Volume 302 cm3 and curved surface area 188 cm2.
  1. Volume = one third pi r2 h = one third x pi x 36 x 8.
  2. one third x 288 = 96, so volume = 96 pi = 301.59, which is 302 cm3.
  3. Curved surface area needs the slant height, found by Pythagoras from the radius and the perpendicular height.
  4. l = the square root of (62 + 82) = the square root of 100 = 10 cm.
  5. Curved surface area = pi r l = pi x 6 x 10 = 188.50, which is 188 cm2 to 3 significant figures.
How the marks are awarded. 1 mark for using one third pi r2 h. 1 mark for 302 cm3. 1 mark for finding the slant height by Pythagoras. 1 mark for a slant height of 10 cm. 1 mark for 188 cm2.
Where students lose the mark. Using the perpendicular height of 8 cm in pi r l. Curved surface area requires the slant height, which must be calculated first.
Question 4[4 marks]

A sphere has a radius of 3 cm. Calculate its volume and its surface area, correct to 3 significant figures.

Show the worked answer
Answer: Volume 113 cm3 and surface area 113 cm2.
  1. Volume = four thirds pi r3 = four thirds x pi x 27.
  2. four thirds x 27 = 36, so volume = 36 pi = 113.10, which is 113 cm3.
  3. Surface area = 4 pi r2 = 4 x pi x 9 = 36 pi = 113.10 cm2.
  4. Both come to 113, which happens only because r = 3. The units differ, cm cubed and cm squared, so the answers are not the same quantity.
How the marks are awarded. 1 mark for using four thirds pi r3. 1 mark for 113 cm3. 1 mark for using 4 pi r2. 1 mark for 113 cm2 with the correct unit.
Where students lose the mark. Cubing 3 as 9 rather than 27. Check every power before substituting, particularly in the sphere formulas.

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Volume and Surface Area FAQs

What is the volume of a cylinder?

Pi multiplied by the radius squared, multiplied by the height. A cylinder is a prism with a circular cross section, so the volume is simply the area of the circular end multiplied by the length or height of the cylinder.

What is the difference between curved and total surface area?

Curved surface area covers only the curved part of the solid. Total surface area adds the flat faces, meaning the two circular ends of a closed cylinder or the circular base of a cone. Read whether the solid is open or closed before deciding.

Which height do I use for a cone?

Use the perpendicular height for the volume and the slant height for the curved surface area. If only one is given, find the other using Pythagoras, since the radius, perpendicular height and slant height form a right-angled triangle.

How do volume and capacity relate?

Capacity is the volume a container can hold. One thousand cubic centimetres equals one litre, and one cubic metre equals one thousand litres. Convert your volume answer to the unit the question asks for before writing the final line.

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Written to the published Cambridge IGCSE Mathematics (0580) syllabus. Check your school entry code and syllabus year, because Core and Extended candidates are assessed on different content. Last reviewed 2026-08-12.