IGCSE Mathematics 0580 · Topic 9.2

IGCSE Mathematics: Averages and Range Practice Questions

The mean is the total divided by how many values there are, the median is the middle value once the data is ordered, and the mode is the most common value. The range is the largest value minus the smallest.

Cambridge IGCSE Mathematics (0580) · Topic 9.2: Averages and Range

Topic 9.2 of Cambridge IGCSE Mathematics 0580 appears in every statistics question that follows. The two versions worth practising hardest are the mean from a frequency table and the estimated mean from grouped data, because both use the same sum of fx method. The questions below build to that.

What you need to know for Averages and Range

IGCSE Mathematics Averages and Range questions and answers

4 exam-style questions written to the 0580 syllabus. Try each one on paper first, then open the worked answer to check your method against the marks.

Question 1[4 marks]

Find the mean, median, mode and range of the data 4, 7, 7, 9, 13.

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Answer: Mean 8, median 7, mode 7, range 9.
  1. Mean: add the values, 4 + 7 + 7 + 9 + 13 = 40, then divide by 5 to get 8.
  2. Median: the data is already ordered and there are 5 values, so the middle one is the third, which is 7.
  3. Mode: 7 appears twice and every other value once, so the mode is 7.
  4. Range: 13 minus 4 = 9.
How the marks are awarded. 1 mark for a mean of 8. 1 mark for a median of 7. 1 mark for a mode of 7. 1 mark for a range of 9.
Where students lose the mark. Finding the median without ordering the data first. Here the values happen to be in order, but in most questions they are not.
Question 2[3 marks]

The mean of five numbers is 12. Four of them are 8, 11, 14 and 15. Calculate the fifth number.

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Answer: 12
  1. The mean is the total divided by the count, so the total is the mean multiplied by the count.
  2. Total of all five numbers = 12 x 5 = 60.
  3. Sum of the four known numbers = 8 + 11 + 14 + 15 = 48.
  4. The fifth number = 60 minus 48 = 12.
How the marks are awarded. 1 mark for finding the total as 60. 1 mark for a partial sum of 48. 1 mark for 12.
Where students lose the mark. Averaging the four known values. The mean of all five is given, so the total must be reconstructed first.
Question 3[4 marks]

A frequency table shows: 0 goals scored in 4 matches, 1 goal in 7 matches, 2 goals in 6 matches and 3 goals in 3 matches. Calculate the mean number of goals per match.

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Answer: 1.4 goals
  1. Multiply each value by its frequency: 0 x 4 = 0, 1 x 7 = 7, 2 x 6 = 12, 3 x 3 = 9.
  2. Add these products to find the sum of fx: 0 + 7 + 12 + 9 = 28 goals in total.
  3. Add the frequencies to find the number of matches: 4 + 7 + 6 + 3 = 20.
  4. Mean = 28 divided by 20 = 1.4 goals per match.
How the marks are awarded. 1 mark for multiplying values by frequencies. 1 mark for a total of 28 goals. 1 mark for a total frequency of 20. 1 mark for 1.4.
Where students lose the mark. Dividing 28 by 4 because there are four rows in the table. The divisor is the total frequency, meaning the number of matches, not the number of categories.
Question 4[5 marks]

Times taken to complete a task are grouped as 0 to 10 minutes (5 people), 10 to 20 minutes (12 people) and 20 to 30 minutes (3 people). Calculate an estimate of the mean time, and explain why it is only an estimate.

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Answer: 13.5 minutes. The exact values within each class are unknown.
  1. Use the midpoint of each class as the representative value: 5, 15 and 25 minutes.
  2. Multiply each midpoint by its frequency: 5 x 5 = 25, 15 x 12 = 180, 25 x 3 = 75.
  3. Sum of fx = 25 + 180 + 75 = 280. Total frequency = 5 + 12 + 3 = 20.
  4. Estimated mean = 280 divided by 20 = 14 minutes.
  5. It is only an estimate because the original data has been grouped, so the individual times are not known. Assuming every value sits at the midpoint of its class introduces error.
How the marks are awarded. 1 mark for using midpoints. 1 mark for correct midpoints of 5, 15 and 25. 1 mark for a sum of fx of 280. 1 mark for 14 minutes. 1 mark for explaining that individual values are unknown once data is grouped.
Where students lose the mark. Using the class boundaries or the class widths instead of the midpoints. The midpoint is the average of the two boundaries of that class.

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Averages and Range FAQs

How do I calculate the mean from a frequency table?

Multiply each value by its frequency, add those products to get the sum of fx, then divide by the total frequency. The divisor is the sum of the frequency column, not the number of rows in the table.

How do I estimate the mean from grouped data?

Use the midpoint of each class as the representative value, multiply each midpoint by its frequency, add the products, and divide by the total frequency. The result is an estimate because the individual values within each class are unknown.

Why is a grouped mean only an estimate?

Once data is grouped, the individual values are lost. Assuming every value sits exactly at the midpoint of its class introduces error, since the real values are spread across the class. The calculated figure is therefore an estimate rather than the true mean.

What is the difference between mean, median and mode?

The mean is the total divided by the number of values and uses every value, so extreme values affect it. The median is the middle value when ordered and is unaffected by extremes. The mode is the most frequently occurring value and is the only average usable for categorical data.

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Written to the published Cambridge IGCSE Mathematics (0580) syllabus. Check your school entry code and syllabus year, because Core and Extended candidates are assessed on different content. Last reviewed 2026-08-12.