IGCSE Chemistry 0620 · Topic 6

IGCSE Chemistry: Chemical Reactions Practice Questions

The rate of a reaction depends on how frequently reacting particles collide with enough energy. Increasing concentration, temperature, surface area or pressure increases the rate, and a catalyst increases it by lowering the activation energy.

Cambridge IGCSE Chemistry (0620) · Topic 6: Chemical Reactions

Topic 6 of Cambridge IGCSE Chemistry 0620 covers rates, equilibrium and redox, and every rate answer must be given in terms of collisions. Naming the factor without the collision explanation loses most of the marks. The questions below train the full explanation each time.

What you need to know for Chemical Reactions

IGCSE Chemistry Chemical Reactions questions and answers

4 exam-style questions written to the 0620 syllabus. Try each one on paper first, then open the worked answer to check your method against the marks.

Question 1[4 marks]

Explain, in terms of particles, why increasing the temperature increases the rate of a reaction.

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Answer: Particles move faster, collide more frequently, and more collisions have energy above the activation energy.
  1. Increasing the temperature increases the average kinetic energy of the particles.
  2. The particles therefore move faster and collide with each other more frequently.
  3. More importantly, a greater proportion of the particles now have energy equal to or greater than the activation energy.
  4. A greater proportion of collisions are therefore successful, so the rate of reaction increases. The second effect is much larger than the first.
How the marks are awarded. 1 mark for increased kinetic energy so particles move faster. 1 mark for more frequent collisions. 1 mark for more particles having energy above the activation energy. 1 mark for a greater proportion of successful collisions.
Where students lose the mark. Giving only more frequent collisions. The dominant reason is that a greater proportion of collisions exceed the activation energy, and that point carries its own mark.
Question 2[3 marks]

Powdered calcium carbonate reacts faster with dilute hydrochloric acid than large lumps of the same mass. Explain why.

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Answer: Powder has a larger surface area, so more particles are exposed and collisions are more frequent.
  1. Breaking a solid into smaller pieces increases the total surface area for the same mass.
  2. More calcium carbonate particles are therefore exposed at the surface where the acid can reach them.
  3. The frequency of collisions between acid particles and the solid surface increases.
  4. More successful collisions occur per second, so the rate of reaction increases. The total volume of gas produced is unchanged, because the mass of calcium carbonate is the same.
How the marks are awarded. 1 mark for a larger surface area. 1 mark for more particles exposed or available to collide. 1 mark for more frequent collisions per second increasing the rate.
Where students lose the mark. Saying the powder has more particles. It has the same number of particles, but more of them are at the exposed surface.
Question 3[4 marks]

Write the equation for the Haber process and state the conditions used, including the catalyst.

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Answer: N2 + 3H2 in equilibrium with 2NH3, at about 450 degrees Celsius, 200 atmospheres, with an iron catalyst.
  1. The reaction is reversible: N2 + 3H2 in equilibrium with 2NH3.
  2. Check the balancing: 2 nitrogen atoms and 6 hydrogen atoms on each side.
  3. The temperature used is around 450 degrees Celsius. This is a compromise, since a lower temperature would give a higher yield but too slow a rate.
  4. The pressure is around 200 atmospheres, and an iron catalyst is used to increase the rate without changing the position of equilibrium.
How the marks are awarded. 1 mark for the correct reversible equation with the equilibrium sign. 1 mark for correct balancing. 1 mark for a temperature of about 450 degrees Celsius and a pressure of about 200 atmospheres. 1 mark for the iron catalyst.
Where students lose the mark. Writing a one way arrow. The Haber process is reversible, and the equilibrium arrow is part of the mark.
Question 4[4 marks]

In the reaction Zn + CuSO4 gives ZnSO4 + Cu, state which species is oxidised and which is reduced, and explain your answer in terms of electrons.

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Answer: Zinc is oxidised because it loses electrons. Copper ions are reduced because they gain electrons.
  1. Zinc starts as a neutral atom and ends as Zn2+ in zinc sulfate, so it has lost two electrons: Zn gives Zn2+ + 2e-.
  2. Loss of electrons is oxidation, so zinc is oxidised. Zinc is therefore the reducing agent.
  3. Copper starts as Cu2+ in copper(II) sulfate and ends as neutral copper metal, so it has gained two electrons: Cu2+ + 2e- gives Cu.
  4. Gain of electrons is reduction, so copper ions are reduced. Copper(II) sulfate is therefore the oxidising agent.
How the marks are awarded. 1 mark for zinc being oxidised. 1 mark for zinc losing electrons, with a correct half equation. 1 mark for copper ions being reduced. 1 mark for copper ions gaining electrons, with a correct half equation.
Where students lose the mark. Saying copper sulfate is reduced. Name the species that actually changes, which is the Cu2+ ion.

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Chemical Reactions FAQs

Why does increasing temperature speed up a reaction?

Higher temperature gives particles more kinetic energy so they move faster and collide more frequently. More significantly, a greater proportion of particles have energy equal to or above the activation energy, so a greater proportion of collisions are successful. The second effect is the larger of the two.

How does a catalyst work?

A catalyst provides an alternative reaction pathway with a lower activation energy. This means a greater proportion of collisions have enough energy to react, so the rate increases. The catalyst is chemically unchanged at the end and does not alter the position of equilibrium or the enthalpy change.

What does equilibrium mean in a reversible reaction?

Equilibrium is reached in a closed system when the forward and reverse reactions are proceeding at the same rate, so the concentrations of reactants and products remain constant. Both reactions continue, which is why it is described as a dynamic equilibrium rather than the reaction stopping.

What is the difference between oxidation and reduction?

Oxidation is the loss of electrons and reduction is the gain of electrons, remembered as OIL RIG. Oxidation can also be described as gain of oxygen or loss of hydrogen. A species that is oxidised acts as the reducing agent, and a species that is reduced acts as the oxidising agent.

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Written to the published Cambridge IGCSE Chemistry (0620) syllabus. Check your school entry code and syllabus year, because Core and Extended candidates are assessed on different content. Last reviewed 2026-08-12.