IGCSE Additional Mathematics 0606 · Topic 2

IGCSE Additional Mathematics: Quadratic Functions Practice Questions

Completing the square gives the turning point and the range of a quadratic. The discriminant b squared minus 4ac decides the number of real roots: positive gives two, zero gives one repeated root, and negative gives none.

Cambridge IGCSE Additional Mathematics (0606) · Topic 2: Quadratic Functions

Topic 2 of Cambridge IGCSE Additional Mathematics 0606 is examined more heavily than almost any other, usually through the discriminant. Questions asking for a range of values of k are where the marks concentrate. The questions below build to those.

What you need to know for Quadratic Functions

IGCSE Additional Mathematics Quadratic Functions questions and answers

4 exam-style questions written to the 0606 syllabus. Try each one on paper first, then open the worked answer to check your method against the marks.

Question 1[4 marks]

Express 2x2 minus 8x + 11 in the form a(x + b)2 + c.

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Answer: 2(x minus 2)2 + 3
  1. Take the coefficient of x2 out of the first two terms: 2(x2 minus 4x) + 11.
  2. Complete the square inside the bracket: x2 minus 4x = (x minus 2)2 minus 4.
  3. Substitute back: 2[(x minus 2)2 minus 4] + 11 = 2(x minus 2)2 minus 8 + 11.
  4. Simplify: 2(x minus 2)2 + 3, so a = 2, b = minus 2 and c = 3.
How the marks are awarded. 1 mark for factorising 2 from the first two terms. 1 mark for completing the square inside the bracket. 1 mark for multiplying the correction by 2. 1 mark for the fully correct form.
Where students lose the mark. Forgetting to multiply the minus 4 by the factor of 2 outside the bracket, which gives an incorrect constant.
Question 2[4 marks]

The equation x2 + kx + 9 = 0 has equal roots. Find the possible values of k.

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Answer: k = 6 or k = minus 6
  1. Equal roots means the discriminant is zero: b2 minus 4ac = 0.
  2. Here a = 1, b = k and c = 9, so k2 minus 4 x 1 x 9 = 0.
  3. k2 minus 36 = 0, so k2 = 36.
  4. k = 6 or k = minus 6. Both values give a perfect square trinomial.
How the marks are awarded. 1 mark for setting the discriminant to zero. 1 mark for correct substitution. 1 mark for k2 = 36. 1 mark for both values of k.
Where students lose the mark. Giving only k = 6. Taking a square root always produces two values unless the context excludes one.
Question 3[4 marks]

Find the range of values of k for which x2 + kx + 9 = 0 has no real roots.

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Answer: minus 6 is less than k, which is less than 6
  1. No real roots means the discriminant is negative: b2 minus 4ac is less than 0.
  2. k2 minus 36 is less than 0, so k2 is less than 36.
  3. The critical values are k = 6 and k = minus 6, from the previous part.
  4. A quadratic in k opening upwards is below zero between its roots, so minus 6 is less than k and k is less than 6.
How the marks are awarded. 1 mark for using the discriminant less than zero. 1 mark for k2 less than 36. 1 mark for the critical values. 1 mark for the correct interval.
Where students lose the mark. Writing k less than 6 alone, or k greater than 6 or k less than minus 6. Sketching the parabola in k shows the solution lies between the roots.
Question 4[3 marks]

State the minimum value of 2x2 minus 8x + 11 and the value of x at which it occurs.

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Answer: Minimum value 3, occurring at x = 2
  1. From the completed square form, 2(x minus 2)2 + 3.
  2. The squared term is never negative, and its least value of zero occurs when x minus 2 = 0, so x = 2.
  3. At that point the function equals 3, so the minimum value is 3. It is a minimum rather than a maximum because the coefficient of x2 is positive.
How the marks are awarded. 1 mark for a minimum value of 3. 1 mark for x = 2. 1 mark for justifying it as a minimum from the positive coefficient.
Where students lose the mark. Reading x = minus 2 from the bracket. The sign reverses, so (x minus 2) squared has its turning point at x = plus 2.

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Quadratic Functions FAQs

What does the discriminant tell you?

The discriminant, b squared minus 4ac, determines the number of real roots. Greater than zero gives two distinct real roots, equal to zero gives one repeated root, and less than zero gives no real roots. It is the standard route into any question about values of an unknown constant.

How do I complete the square when there is a coefficient in front of x squared?

Factorise that coefficient out of the first two terms only, complete the square inside the bracket, then multiply the correction term by the factor when you expand back out. Forgetting to multiply the correction is the most common error.

How do I find the range of values for no real roots?

Set the discriminant less than zero, which usually gives a quadratic inequality in the unknown. Find the critical values by solving the corresponding equation, then sketch the parabola to decide whether the solution lies between the roots or outside them.

How do I read the turning point from completed square form?

For a(x plus b) squared plus c, the turning point is at x equals minus b with y equals c. The sign inside the bracket reverses, so 2(x minus 2) squared plus 3 has its turning point at the point (2, 3).

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Written to the published Cambridge IGCSE Additional Mathematics (0606) syllabus. Check your school entry code and syllabus year, because Core and Extended candidates are assessed on different content. Last reviewed 2026-08-12.